Base | Representation |
---|---|
bin | 111101100001101001… |
… | …1101011011101100001 |
3 | 110122001001212202111121 |
4 | 1323003103223131201 |
5 | 4131043142003003 |
6 | 140410413012241 |
7 | 12355125133525 |
oct | 1730323533541 |
9 | 418031782447 |
10 | 132125734753 |
11 | 51041595111 |
12 | 21734784081 |
13 | c5c840314c |
14 | 6575933d85 |
15 | 36847b0cbd |
hex | 1ec34eb761 |
132125734753 has 4 divisors (see below), whose sum is σ = 132401571840. Its totient is φ = 131849897668.
The previous prime is 132125734739. The next prime is 132125734759. The reversal of 132125734753 is 357437521231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 132125734753 - 25 = 132125734721 is a prime.
It is a super-2 number, since 2×1321257347532 (a number of 23 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132125734759) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 137917825 + ... + 137918782.
It is an arithmetic number, because the mean of its divisors is an integer number (33100392960).
Almost surely, 2132125734753 is an apocalyptic number.
It is an amenable number.
132125734753 is a deficient number, since it is larger than the sum of its proper divisors (275837087).
132125734753 is an equidigital number, since it uses as much as digits as its factorization.
132125734753 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 275837086.
The product of its digits is 529200, while the sum is 43.
The spelling of 132125734753 in words is "one hundred thirty-two billion, one hundred twenty-five million, seven hundred thirty-four thousand, seven hundred fifty-three".
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