Base | Representation |
---|---|
bin | 11110000010101111101001… |
… | …111110000111010110010011 |
3 | 122022211111122011212220111112 |
4 | 132002233221332013112103 |
5 | 114304304222100114303 |
6 | 1145003404102203535 |
7 | 36555035452430036 |
oct | 3602575176072623 |
9 | 568744564786445 |
10 | 132130004301203 |
11 | 39112024895757 |
12 | 1299b81b1235ab |
13 | 5895a62868a6c |
14 | 248b1aa91701d |
15 | 10420109890d8 |
hex | 782be9f87593 |
132130004301203 has 4 divisors (see below), whose sum is σ = 132238574560680. Its totient is φ = 132021434041728.
The previous prime is 132130004301199. The next prime is 132130004301221. The reversal of 132130004301203 is 302103400031231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132130004301203 - 22 = 132130004301199 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132130004301803) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54285127913 + ... + 54285130346.
It is an arithmetic number, because the mean of its divisors is an integer number (33059643640170).
Almost surely, 2132130004301203 is an apocalyptic number.
132130004301203 is a deficient number, since it is larger than the sum of its proper divisors (108570259477).
132130004301203 is a wasteful number, since it uses less digits than its factorization.
132130004301203 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 108570259476.
The product of its (nonzero) digits is 1296, while the sum is 23.
Adding to 132130004301203 its reverse (302103400031231), we get a palindrome (434233404332434).
The spelling of 132130004301203 in words is "one hundred thirty-two trillion, one hundred thirty billion, four million, three hundred one thousand, two hundred three".
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