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132135035 = 526427007
BaseRepresentation
bin1111110000000…
…11100001111011
3100012122011012012
413320003201323
5232311310120
621040040135
73163062224
oct770034173
9305564165
10132135035
116865000a
123830304b
13214b5516
141379824b
15b9011c5
hex7e0387b

132135035 has 4 divisors (see below), whose sum is σ = 158562048. Its totient is φ = 105708024.

The previous prime is 132135019. The next prime is 132135041. The reversal of 132135035 is 530531231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 530531231 = 1094867259.

It is a cyclic number.

It is not a de Polignac number, because 132135035 - 24 = 132135019 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 132135035.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13213499 + ... + 13213508.

It is an arithmetic number, because the mean of its divisors is an integer number (39640512).

Almost surely, 2132135035 is an apocalyptic number.

132135035 is a deficient number, since it is larger than the sum of its proper divisors (26427013).

132135035 is an equidigital number, since it uses as much as digits as its factorization.

132135035 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26427012.

The product of its (nonzero) digits is 1350, while the sum is 23.

The square root of 132135035 is about 11495.0004349717. Note that the first 3 decimals coincide. The cubic root of 132135035 is about 509.3379015474.

Adding to 132135035 its reverse (530531231), we get a palindrome (662666266).

The spelling of 132135035 in words is "one hundred thirty-two million, one hundred thirty-five thousand, thirty-five".

Divisors: 1 5 26427007 132135035