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132143343444451 = 165779748547643
BaseRepresentation
bin11110000010111100000101…
…000010111010000111100011
3122022212210001210211121001001
4132002330011002322013203
5114310014031410210301
61145013451450252431
736556020144323353
oct3602740502720743
9568783053747031
10132143343444451
113911774a44a489
12129a2322427117
1358970aa292131
14248bab4324b63
151042541a7cc01
hex782f050ba1e3

132143343444451 has 4 divisors (see below), whose sum is σ = 132223091993752. Its totient is φ = 132063594895152.

The previous prime is 132143343444449. The next prime is 132143343444457. The reversal of 132143343444451 is 154444343341231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132143343444451 - 21 = 132143343444449 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132143343444457) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 39874272165 + ... + 39874275478.

It is an arithmetic number, because the mean of its divisors is an integer number (33055772998438).

Almost surely, 2132143343444451 is an apocalyptic number.

132143343444451 is a deficient number, since it is larger than the sum of its proper divisors (79748549301).

132143343444451 is an equidigital number, since it uses as much as digits as its factorization.

132143343444451 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 79748549300.

The product of its digits is 3317760, while the sum is 46.

Adding to 132143343444451 its reverse (154444343341231), we get a palindrome (286587686785682).

The spelling of 132143343444451 in words is "one hundred thirty-two trillion, one hundred forty-three billion, three hundred forty-three million, four hundred forty-four thousand, four hundred fifty-one".

Divisors: 1 1657 79748547643 132143343444451