Base | Representation |
---|---|
bin | 111101100010001100… |
… | …1011010100000000001 |
3 | 110122002100021111210011 |
4 | 1323010121122200001 |
5 | 4131112331442421 |
6 | 140412304504521 |
7 | 12355436412001 |
oct | 1730431324001 |
9 | 418070244704 |
10 | 132144015361 |
11 | 51050940656 |
12 | 2173a91b141 |
13 | c5cc133a87 |
14 | 6578132001 |
15 | 36861c24e1 |
hex | 1ec465a801 |
132144015361 has 4 divisors (see below), whose sum is σ = 132206027824. Its totient is φ = 132082002900.
The previous prime is 132144015337. The next prime is 132144015407. The reversal of 132144015361 is 163510441231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 163510441231 = 71 ⋅2302963961.
It is a cyclic number.
It is not a de Polignac number, because 132144015361 - 27 = 132144015233 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132144015331) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31003035 + ... + 31007296.
It is an arithmetic number, because the mean of its divisors is an integer number (33051506956).
Almost surely, 2132144015361 is an apocalyptic number.
It is an amenable number.
132144015361 is a deficient number, since it is larger than the sum of its proper divisors (62012463).
132144015361 is an equidigital number, since it uses as much as digits as its factorization.
132144015361 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62012462.
The product of its (nonzero) digits is 8640, while the sum is 31.
Adding to 132144015361 its reverse (163510441231), we get a palindrome (295654456592).
The spelling of 132144015361 in words is "one hundred thirty-two billion, one hundred forty-four million, fifteen thousand, three hundred sixty-one".
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