132151142413001 has 4 divisors (see below), whose sum is σ = 133101870056400. Its totient is φ = 131200414769604.

The previous prime is 132151142412953. The next prime is 132151142413007. The reversal of 132151142413001 is 100314241151231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132151142413001 is a prime.

It is a super-2 number, since 2×132151142413001² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132151142413007) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 475363821491 + ... + 475363821768.

It is an arithmetic number, because the mean of its divisors is an integer number (33275467514100).

Almost surely, 2^{132151142413001} is an apocalyptic number.

It is an amenable number.

132151142413001 is a deficient number, since it is larger than the sum of its proper divisors (950727643399).

132151142413001 is an equidigital number, since it uses as much as digits as its factorization.

132151142413001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 950727643398.

The product of its (nonzero) digits is 2880, while the sum is 29.

Adding to 132151142413001 its reverse (100314241151231), we get a palindrome (232465383564232).

The spelling of 132151142413001 in words is "one hundred thirty-two trillion, one hundred fifty-one billion, one hundred forty-two million, four hundred thirteen thousand, one".