Base | Representation |
---|---|
bin | 11110000011000101011110… |
… | …111111110100110101110001 |
3 | 122022220202010122000210212020 |
4 | 132003011132333310311301 |
5 | 114310200222241123213 |
6 | 1145022241532422053 |
7 | 36556525334131515 |
oct | 3603053677646561 |
9 | 568822118023766 |
10 | 132153442520433 |
11 | 39120a62084774 |
12 | 129a4280617929 |
13 | 589802965b639 |
14 | 248c3916b8145 |
15 | 10429334ab923 |
hex | 78315eff4d71 |
132153442520433 has 8 divisors (see below), whose sum is σ = 176204710611648. Its totient is φ = 88102234721424.
The previous prime is 132153442520417. The next prime is 132153442520447. The reversal of 132153442520433 is 334025244351231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 132153442520433 - 24 = 132153442520417 is a prime.
It is not an unprimeable number, because it can be changed into a prime (132153442500433) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9683341 + ... + 18922842.
It is an arithmetic number, because the mean of its divisors is an integer number (22025588826456).
Almost surely, 2132153442520433 is an apocalyptic number.
It is an amenable number.
132153442520433 is a deficient number, since it is larger than the sum of its proper divisors (44051268091215).
132153442520433 is a wasteful number, since it uses less digits than its factorization.
132153442520433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 30146103.
The product of its (nonzero) digits is 1036800, while the sum is 42.
Adding to 132153442520433 its reverse (334025244351231), we get a palindrome (466178686871664).
The spelling of 132153442520433 in words is "one hundred thirty-two trillion, one hundred fifty-three billion, four hundred forty-two million, five hundred twenty thousand, four hundred thirty-three".
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