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132153442520433 = 3153991728606183
BaseRepresentation
bin11110000011000101011110…
…111111110100110101110001
3122022220202010122000210212020
4132003011132333310311301
5114310200222241123213
61145022241532422053
736556525334131515
oct3603053677646561
9568822118023766
10132153442520433
1139120a62084774
12129a4280617929
13589802965b639
14248c3916b8145
1510429334ab923
hex78315eff4d71

132153442520433 has 8 divisors (see below), whose sum is σ = 176204710611648. Its totient is φ = 88102234721424.

The previous prime is 132153442520417. The next prime is 132153442520447. The reversal of 132153442520433 is 334025244351231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 132153442520433 - 24 = 132153442520417 is a prime.

It is not an unprimeable number, because it can be changed into a prime (132153442500433) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 9683341 + ... + 18922842.

It is an arithmetic number, because the mean of its divisors is an integer number (22025588826456).

Almost surely, 2132153442520433 is an apocalyptic number.

It is an amenable number.

132153442520433 is a deficient number, since it is larger than the sum of its proper divisors (44051268091215).

132153442520433 is a wasteful number, since it uses less digits than its factorization.

132153442520433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 30146103.

The product of its (nonzero) digits is 1036800, while the sum is 42.

Adding to 132153442520433 its reverse (334025244351231), we get a palindrome (466178686871664).

The spelling of 132153442520433 in words is "one hundred thirty-two trillion, one hundred fifty-three billion, four hundred forty-two million, five hundred twenty thousand, four hundred thirty-three".

Divisors: 1 3 1539917 4619751 28606183 85818549 44051147506811 132153442520433