Base | Representation |
---|---|
bin | 11110000011000111011011… |
… | …101011010111101111010011 |
3 | 122022220221112102002202012001 |
4 | 132003013123223113233103 |
5 | 114310214013240412410 |
6 | 1145023225255014431 |
7 | 36556631224062433 |
oct | 3603073353275723 |
9 | 568827472082161 |
10 | 132155534310355 |
11 | 39121935915476 |
12 | 129a476506a417 |
13 | 58982a0b3355a |
14 | 248c50d4282c3 |
15 | 1042a06e5133a |
hex | 7831dbad7bd3 |
132155534310355 has 8 divisors (see below), whose sum is σ = 161274550345200. Its totient is φ = 103932487999776.
The previous prime is 132155534310343. The next prime is 132155534310413. The reversal of 132155534310355 is 553013435551231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132155534310355 - 211 = 132155534308307 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 223992430740 + ... + 223992431329.
It is an arithmetic number, because the mean of its divisors is an integer number (20159318793150).
Almost surely, 2132155534310355 is an apocalyptic number.
132155534310355 is a deficient number, since it is larger than the sum of its proper divisors (29119016034845).
132155534310355 is an equidigital number, since it uses as much as digits as its factorization.
132155534310355 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 447984862133.
The product of its (nonzero) digits is 2025000, while the sum is 46.
Adding to 132155534310355 its reverse (553013435551231), we get a palindrome (685168969861586).
The spelling of 132155534310355 in words is "one hundred thirty-two trillion, one hundred fifty-five billion, five hundred thirty-four million, three hundred ten thousand, three hundred fifty-five".
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