Base | Representation |
---|---|
bin | 11110000011001000010101… |
… | …111101111001100101111011 |
3 | 122022221001001120021000212220 |
4 | 132003020111331321211323 |
5 | 114310223014113334024 |
6 | 1145023510311335123 |
7 | 36556664400306243 |
oct | 3603102575714573 |
9 | 568831046230786 |
10 | 132156512246139 |
11 | 39122297939067 |
12 | 129a49986814a3 |
13 | 58983c8616894 |
14 | 248c5a3270b23 |
15 | 1042a62c24e79 |
hex | 783215f7997b |
132156512246139 has 16 divisors (see below), whose sum is σ = 191124482562720. Its totient is φ = 80899251875840.
The previous prime is 132156512246113. The next prime is 132156512246149. The reversal of 132156512246139 is 931642215651231.
It is a cyclic number.
It is not a de Polignac number, because 132156512246139 - 212 = 132156512242043 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (51).
It is a junction number, because it is equal to n+sod(n) for n = 132156512246091 and 132156512246100.
It is not an unprimeable number, because it can be changed into a prime (132156512246149) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 31601268174 + ... + 31601272355.
It is an arithmetic number, because the mean of its divisors is an integer number (11945280160170).
Almost surely, 2132156512246139 is an apocalyptic number.
132156512246139 is a deficient number, since it is larger than the sum of its proper divisors (58967970316581).
132156512246139 is a wasteful number, since it uses less digits than its factorization.
132156512246139 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 63202540590.
The product of its digits is 2332800, while the sum is 51.
The spelling of 132156512246139 in words is "one hundred thirty-two trillion, one hundred fifty-six billion, five hundred twelve million, two hundred forty-six thousand, one hundred thirty-nine".
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