1322012010113 has 4 divisors (see below), whose sum is σ = 1341743532720. Its totient is φ = 1302280487508.

The previous prime is 1322012010049. The next prime is 1322012010119. The reversal of 1322012010113 is 3110102102231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1322012010113 - 2⁶ = 1322012010049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1322012010091 and 1322012010100.

It is not an unprimeable number, because it can be changed into a prime (1322012010119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 9865761203 + ... + 9865761336.

It is an arithmetic number, because the mean of its divisors is an integer number (335435883180).

Almost surely, 2^{1322012010113} is an apocalyptic number.

It is an amenable number.

1322012010113 is a deficient number, since it is larger than the sum of its proper divisors (19731522607).

1322012010113 is an equidigital number, since it uses as much as digits as its factorization.

1322012010113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 19731522606.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 1322012010113 its reverse (3110102102231), we get a palindrome (4432114112344).

The spelling of 1322012010113 in words is "one trillion, three hundred twenty-two billion, twelve million, ten thousand, one hundred thirteen".