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132202151353 = 469128182083
BaseRepresentation
bin111101100011111011…
…1001011110110111001
3110122020101200010101001
41323013313023312321
54131222222320403
6140422142525001
712360043513456
oct1730767136671
9418211603331
10132202151353
1151080739028
1221756296761
13c60b1aa47c
146581b4682d
15368b357c1d
hex1ec7dcbdb9

132202151353 has 4 divisors (see below), whose sum is σ = 132230338128. Its totient is φ = 132173964580.

The previous prime is 132202151339. The next prime is 132202151371. The reversal of 132202151353 is 353151202231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132202151353 - 25 = 132202151321 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132202152353) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14086351 + ... + 14095732.

It is an arithmetic number, because the mean of its divisors is an integer number (33057584532).

Almost surely, 2132202151353 is an apocalyptic number.

It is an amenable number.

132202151353 is a deficient number, since it is larger than the sum of its proper divisors (28186775).

132202151353 is an equidigital number, since it uses as much as digits as its factorization.

132202151353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28186774.

The product of its (nonzero) digits is 5400, while the sum is 28.

Adding to 132202151353 its reverse (353151202231), we get a palindrome (485353353584).

The spelling of 132202151353 in words is "one hundred thirty-two billion, two hundred two million, one hundred fifty-one thousand, three hundred fifty-three".

Divisors: 1 4691 28182083 132202151353