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13220301113 = 15187551663
BaseRepresentation
bin11000100111111110…
…11100100100111001
31021010100022212202222
430103333130210321
5204033344113423
610023500533425
7645416463635
oct142377344471
937110285688
1013220301113
115674573998
12268b551275
131328c164a6
148d5b13dc5
1552596b3c8
hex313fdc939

13220301113 has 4 divisors (see below), whose sum is σ = 13307852928. Its totient is φ = 13132749300.

The previous prime is 13220301103. The next prime is 13220301167. The reversal of 13220301113 is 31110302231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13220301113 - 26 = 13220301049 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13220301091 and 13220301100.

It is not an unprimeable number, because it can be changed into a prime (13220301103) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43775681 + ... + 43775982.

It is an arithmetic number, because the mean of its divisors is an integer number (3326963232).

Almost surely, 213220301113 is an apocalyptic number.

It is an amenable number.

13220301113 is a deficient number, since it is larger than the sum of its proper divisors (87551815).

13220301113 is an equidigital number, since it uses as much as digits as its factorization.

13220301113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 87551814.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 13220301113 its reverse (31110302231), we get a palindrome (44330603344).

The spelling of 13220301113 in words is "thirteen billion, two hundred twenty million, three hundred one thousand, one hundred thirteen".

Divisors: 1 151 87551663 13220301113