Base | Representation |
---|---|
bin | 11000100111111110… |
… | …11111110000010011 |
3 | 1021010100100112122010 |
4 | 30103333133300103 |
5 | 204033400023011 |
6 | 10023501114003 |
7 | 645416546613 |
oct | 142377376023 |
9 | 37110315563 |
10 | 13220314131 |
11 | 5674582752 |
12 | 268b558903 |
13 | 1328c1c3ab |
14 | 8d5b18a43 |
15 | 5259701a6 |
hex | 313fdfc13 |
13220314131 has 8 divisors (see below), whose sum is σ = 17665323984. Its totient is φ = 8794423520.
The previous prime is 13220314103. The next prime is 13220314169. The reversal of 13220314131 is 13141302231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13220314131 - 26 = 13220314067 is a prime.
It is a super-2 number, since 2×132203141312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13220314098 and 13220314107.
It is not an unprimeable number, because it can be changed into a prime (13220319131) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 4778196 + ... + 4780961.
It is an arithmetic number, because the mean of its divisors is an integer number (2208165498).
Almost surely, 213220314131 is an apocalyptic number.
13220314131 is a deficient number, since it is larger than the sum of its proper divisors (4445009853).
13220314131 is an equidigital number, since it uses as much as digits as its factorization.
13220314131 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 9559621.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 13220314131 its reverse (13141302231), we get a palindrome (26361616362).
The spelling of 13220314131 in words is "thirteen billion, two hundred twenty million, three hundred fourteen thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.069 sec. • engine limits •