1322040113 has 8 divisors (see below), whose sum is σ = 1331232000. Its totient is φ = 1312877808.

The previous prime is 1322040103. The next prime is 1322040143. The reversal of 1322040113 is 3110402231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1322040113 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1322040091 and 1322040100.

It is not an unprimeable number, because it can be changed into a prime (1322040103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 86363 + ... + 100511.

It is an arithmetic number, because the mean of its divisors is an integer number (166404000).

Almost surely, 2^1322040113 is an apocalyptic number.

It is an amenable number.

1322040113 is a deficient number, since it is larger than the sum of its proper divisors (9191887).

1322040113 is a wasteful number, since it uses less digits than its factorization.

1322040113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 14791.

The product of its (nonzero) digits is 144, while the sum is 17.

The square root of 1322040113 is about 36359.8695404700. The cubic root of 1322040113 is about 1097.5261521746.

Adding to 1322040113 its reverse (3110402231), we get a palindrome (4432442344).

The spelling of 1322040113 in words is "one billion, three hundred twenty-two million, forty thousand, one hundred thirteen".