Base | Representation |
---|---|
bin | 1100000001100001111010… |
… | …0101001110010010110001 |
3 | 1201210212012222011012120211 |
4 | 3000120132211032102301 |
5 | 3213100411114131231 |
6 | 44041213405504121 |
7 | 2533100251235500 |
oct | 300303645162261 |
9 | 51725188135524 |
10 | 13220422411441 |
11 | 4237827882983 |
12 | 1596258872041 |
13 | 74b8b003c6cb |
14 | 339c2c548837 |
15 | 17dd609b5eb1 |
hex | c061e94e4b1 |
13220422411441 has 12 divisors (see below), whose sum is σ = 15736506603312. Its totient is φ = 11068260621768.
The previous prime is 13220422411403. The next prime is 13220422411457. The reversal of 13220422411441 is 14411422402231.
It is not a de Polignac number, because 13220422411441 - 239 = 12670666597553 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13220422411241) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 3137259975 + ... + 3137264188.
It is an arithmetic number, because the mean of its divisors is an integer number (1311375550276).
Almost surely, 213220422411441 is an apocalyptic number.
It is an amenable number.
13220422411441 is a deficient number, since it is larger than the sum of its proper divisors (2516084191871).
13220422411441 is an equidigital number, since it uses as much as digits as its factorization.
13220422411441 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6274524220 (or 6274524213 counting only the distinct ones).
The product of its (nonzero) digits is 12288, while the sum is 31.
Adding to 13220422411441 its reverse (14411422402231), we get a palindrome (27631844813672).
The spelling of 13220422411441 in words is "thirteen trillion, two hundred twenty billion, four hundred twenty-two million, four hundred eleven thousand, four hundred forty-one".
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