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132210221113 = 163811105651
BaseRepresentation
bin111101100100001010…
…1111110000000111001
3110122020221212010000001
41323020111332000321
54131231304033423
6140423031513001
712360202223455
oct1731025760071
9418227763001
10132210221113
115108524aa53
1221758b28761
13c60ca74589
146582c47665
15368bdedcad
hex1ec857e039

132210221113 has 4 divisors (see below), whose sum is σ = 133021326928. Its totient is φ = 131399115300.

The previous prime is 132210221081. The next prime is 132210221123. The reversal of 132210221113 is 311122012231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132210221113 - 25 = 132210221081 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132210221123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 405552663 + ... + 405552988.

It is an arithmetic number, because the mean of its divisors is an integer number (33255331732).

Almost surely, 2132210221113 is an apocalyptic number.

It is an amenable number.

132210221113 is a deficient number, since it is larger than the sum of its proper divisors (811105815).

132210221113 is an equidigital number, since it uses as much as digits as its factorization.

132210221113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 811105814.

The product of its (nonzero) digits is 144, while the sum is 19.

Adding to 132210221113 its reverse (311122012231), we get a palindrome (443332233344).

The spelling of 132210221113 in words is "one hundred thirty-two billion, two hundred ten million, two hundred twenty-one thousand, one hundred thirteen".

Divisors: 1 163 811105651 132210221113