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132211125433 = 484732727521
BaseRepresentation
bin111101100100001100…
…1011010110010111001
3110122021000120001111101
41323020121122302321
54131232022003213
6140423103131401
712360213011122
oct1731031326271
9418230501441
10132211125433
1151085808422
12217592a3b61
13c61000008a
146583001049
15368c02bbdd
hex1ec865acb9

132211125433 has 4 divisors (see below), whose sum is σ = 132213901428. Its totient is φ = 132208349440.

The previous prime is 132211125427. The next prime is 132211125451. The reversal of 132211125433 is 334521112231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 35979640489 + 96231484944 = 189683^2 + 310212^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-132211125433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132211125413) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1315288 + ... + 1412233.

It is an arithmetic number, because the mean of its divisors is an integer number (33053475357).

Almost surely, 2132211125433 is an apocalyptic number.

It is an amenable number.

132211125433 is a deficient number, since it is larger than the sum of its proper divisors (2775995).

132211125433 is an equidigital number, since it uses as much as digits as its factorization.

132211125433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2775994.

The product of its digits is 4320, while the sum is 28.

Adding to 132211125433 its reverse (334521112231), we get a palindrome (466732237664).

The spelling of 132211125433 in words is "one hundred thirty-two billion, two hundred eleven million, one hundred twenty-five thousand, four hundred thirty-three".

Divisors: 1 48473 2727521 132211125433