1322121130033 has 4 divisors (see below), whose sum is σ = 1442313960048. Its totient is φ = 1201928300020.

The previous prime is 1322121130013. The next prime is 1322121130049. The reversal of 1322121130033 is 3300311212231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1322121130033 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1322121129986 and 1322121130013.

It is not an unprimeable number, because it can be changed into a prime (1322121130013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 60096414991 + ... + 60096415012.

It is an arithmetic number, because the mean of its divisors is an integer number (360578490012).

Almost surely, 2^{1322121130033} is an apocalyptic number.

It is an amenable number.

1322121130033 is a deficient number, since it is larger than the sum of its proper divisors (120192830015).

1322121130033 is a wasteful number, since it uses less digits than its factorization.

1322121130033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 120192830014.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 1322121130033 its reverse (3300311212231), we get a palindrome (4622432342264).

The spelling of 1322121130033 in words is "one trillion, three hundred twenty-two billion, one hundred twenty-one million, one hundred thirty thousand, thirty-three".