132213112100113 has 4 divisors (see below), whose sum is σ = 144232485927408. Its totient is φ = 120193738272820.

The previous prime is 132213112100077. The next prime is 132213112100119. The reversal of 132213112100113 is 311001211312231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-132213112100113 is a prime.

It is a super-3 number, since 3×132213112100113³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132213112100119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6009686913631 + ... + 6009686913652.

It is an arithmetic number, because the mean of its divisors is an integer number (36058121481852).

Almost surely, 2^{132213112100113} is an apocalyptic number.

It is an amenable number.

132213112100113 is a deficient number, since it is larger than the sum of its proper divisors (12019373827295).

132213112100113 is a wasteful number, since it uses less digits than its factorization.

132213112100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12019373827294.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 132213112100113 its reverse (311001211312231), we get a palindrome (443214323412344).

The spelling of 132213112100113 in words is "one hundred thirty-two trillion, two hundred thirteen billion, one hundred twelve million, one hundred thousand, one hundred thirteen".