Base | Representation |
---|---|
bin | 11110000011111110000100… |
… | …100111111001011010000011 |
3 | 122100010112222011012102221122 |
4 | 132003332010213321122003 |
5 | 114312144142022332120 |
6 | 1145110211055342455 |
7 | 36564106132342520 |
oct | 3603760447713203 |
9 | 570115864172848 |
10 | 132214203324035 |
11 | 39144801a60838 |
12 | 129b3bb9221a2b |
13 | 58a09908c6871 |
14 | 24912b7212147 |
15 | 10442dc8e2a25 |
hex | 783f849f9683 |
132214203324035 has 16 divisors (see below), whose sum is σ = 182324116857792. Its totient is φ = 90160277558400.
The previous prime is 132214203324019. The next prime is 132214203324053. The reversal of 132214203324035 is 530423302412231.
It is not a de Polignac number, because 132214203324035 - 24 = 132214203324019 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (35).
It is a junction number, because it is equal to n+sod(n) for n = 132214203323986 and 132214203324004.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10435210976 + ... + 10435223645.
It is an arithmetic number, because the mean of its divisors is an integer number (11395257303612).
Almost surely, 2132214203324035 is an apocalyptic number.
132214203324035 is a deficient number, since it is larger than the sum of its proper divisors (50109913533757).
132214203324035 is a wasteful number, since it uses less digits than its factorization.
132214203324035 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 20870434814.
The product of its (nonzero) digits is 103680, while the sum is 35.
Adding to 132214203324035 its reverse (530423302412231), we get a palindrome (662637505736266).
The spelling of 132214203324035 in words is "one hundred thirty-two trillion, two hundred fourteen billion, two hundred three million, three hundred twenty-four thousand, thirty-five".
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