Base | Representation |
---|---|
bin | 11110000011111110011111… |
… | …010101000010001010101011 |
3 | 122100010121010101021020020211 |
4 | 132003332133111002022223 |
5 | 114312201101222122021 |
6 | 1145110323342401551 |
7 | 36564123212536516 |
oct | 3603763725021253 |
9 | 570117111236224 |
10 | 132214651364011 |
11 | 39144a11958907 |
12 | 129b41032902b7 |
13 | 58a0a32688388 |
14 | 249131a91dd7d |
15 | 1044316de53e1 |
hex | 783f9f5422ab |
132214651364011 has 4 divisors (see below), whose sum is σ = 134188004369512. Its totient is φ = 130241298358512.
The previous prime is 132214651363967. The next prime is 132214651364041. The reversal of 132214651364011 is 110463156412231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132214651364011 - 213 = 132214651355819 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132214651364041) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 986676502650 + ... + 986676502783.
It is an arithmetic number, because the mean of its divisors is an integer number (33547001092378).
Almost surely, 2132214651364011 is an apocalyptic number.
132214651364011 is a deficient number, since it is larger than the sum of its proper divisors (1973353005501).
132214651364011 is an equidigital number, since it uses as much as digits as its factorization.
132214651364011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1973353005500.
The product of its (nonzero) digits is 103680, while the sum is 40.
The spelling of 132214651364011 in words is "one hundred thirty-two trillion, two hundred fourteen billion, six hundred fifty-one million, three hundred sixty-four thousand, eleven".
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