Base | Representation |
---|---|
bin | 111101100100010100… |
… | …0010010111011111001 |
3 | 110122021021220012020122 |
4 | 1323020220102323321 |
5 | 4131234021303101 |
6 | 140423322503025 |
7 | 12360261113234 |
oct | 1731050227371 |
9 | 418237805218 |
10 | 132215025401 |
11 | 51087a31538 |
12 | 2175a664a75 |
13 | c610a67254 |
14 | 658373841b |
15 | 368c54c51b |
hex | 1ec8a12ef9 |
132215025401 has 4 divisors (see below), whose sum is σ = 133450679952. Its totient is φ = 130979370852.
The previous prime is 132215025359. The next prime is 132215025473. The reversal of 132215025401 is 104520512231.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 132215025401 - 210 = 132215024377 is a prime.
It is a Duffinian number.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (132215025101) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 617827115 + ... + 617827328.
It is an arithmetic number, because the mean of its divisors is an integer number (33362669988).
Almost surely, 2132215025401 is an apocalyptic number.
It is an amenable number.
132215025401 is a deficient number, since it is larger than the sum of its proper divisors (1235654551).
132215025401 is a wasteful number, since it uses less digits than its factorization.
132215025401 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1235654550.
The product of its (nonzero) digits is 2400, while the sum is 26.
Adding to 132215025401 its reverse (104520512231), we get a palindrome (236735537632).
The spelling of 132215025401 in words is "one hundred thirty-two billion, two hundred fifteen million, twenty-five thousand, four hundred one".
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