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1322200230113 = 7188885747159
BaseRepresentation
bin10011001111011001010…
…001100110100011100001
311200101211101222222210002
4103033121101212203201
5133130331224330423
62451224351345345
7164345232343340
oct23173121464341
94611741888702
101322200230113
1146a818618704
12194302222255
13978b5584389
1447dcdb6bb57
15245d7e06228
hex133d94668e1

1322200230113 has 4 divisors (see below), whose sum is σ = 1511085977280. Its totient is φ = 1133314482948.

The previous prime is 1322200230041. The next prime is 1322200230119. The reversal of 1322200230113 is 3110320022231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1322200230113 - 210 = 1322200229089 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1322200230119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 94442873573 + ... + 94442873586.

It is an arithmetic number, because the mean of its divisors is an integer number (377771494320).

Almost surely, 21322200230113 is an apocalyptic number.

It is an amenable number.

1322200230113 is a deficient number, since it is larger than the sum of its proper divisors (188885747167).

1322200230113 is an equidigital number, since it uses as much as digits as its factorization.

1322200230113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 188885747166.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 1322200230113 its reverse (3110320022231), we get a palindrome (4432520252344).

The spelling of 1322200230113 in words is "one trillion, three hundred twenty-two billion, two hundred million, two hundred thirty thousand, one hundred thirteen".

Divisors: 1 7 188885747159 1322200230113