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13222014403 = 131017078031
BaseRepresentation
bin11000101000001011…
…11110110111000011
31021010110112220222011
430110011332313003
5204034313430103
610024001353351
7645440160643
oct142405766703
937113486864
1013222014403
115675534134
122690038857
131329396280
148d603c523
15525ba8d6d
hex31417edc3

13222014403 has 4 divisors (see below), whose sum is σ = 14239092448. Its totient is φ = 12204936360.

The previous prime is 13222014389. The next prime is 13222014427. The reversal of 13222014403 is 30441022231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13222014403 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13222014203) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 508539003 + ... + 508539028.

It is an arithmetic number, because the mean of its divisors is an integer number (3559773112).

Almost surely, 213222014403 is an apocalyptic number.

13222014403 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

13222014403 is a deficient number, since it is larger than the sum of its proper divisors (1017078045).

13222014403 is a wasteful number, since it uses less digits than its factorization.

13222014403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1017078044.

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 13222014403 its reverse (30441022231), we get a palindrome (43663036634).

The spelling of 13222014403 in words is "thirteen billion, two hundred twenty-two million, fourteen thousand, four hundred three".

Divisors: 1 13 1017078031 13222014403