Base | Representation |
---|---|
bin | 1100000001101000010100… |
… | …0110001111100011110011 |
3 | 1201211000122211111210200220 |
4 | 3000122011012033203303 |
5 | 3213112421414442121 |
6 | 44042100205544123 |
7 | 2533161004354431 |
oct | 300320506174363 |
9 | 51730584453626 |
10 | 13222142343411 |
11 | 423852a71a261 |
12 | 1596658875043 |
13 | 74bac5477431 |
14 | 339d52b3bd51 |
15 | 17de119a56c6 |
hex | c068518f8f3 |
13222142343411 has 8 divisors (see below), whose sum is σ = 17656940736960. Its totient is φ = 8801052756072.
The previous prime is 13222142343409. The next prime is 13222142343439. The reversal of 13222142343411 is 11434324122231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13222142343411 - 21 = 13222142343409 is a prime.
It is a super-2 number, since 2×132221423434112 (a number of 27 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (13222142343461) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3427199301 + ... + 3427203158.
It is an arithmetic number, because the mean of its divisors is an integer number (2207117592120).
Almost surely, 213222142343411 is an apocalyptic number.
13222142343411 is a deficient number, since it is larger than the sum of its proper divisors (4434798393549).
13222142343411 is an equidigital number, since it uses as much as digits as its factorization.
13222142343411 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6854403105.
The product of its digits is 27648, while the sum is 33.
Adding to 13222142343411 its reverse (11434324122231), we get a palindrome (24656466465642).
The spelling of 13222142343411 in words is "thirteen trillion, two hundred twenty-two billion, one hundred forty-two million, three hundred forty-three thousand, four hundred eleven".
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