Base | Representation |
---|---|
bin | 11000101000001101… |
… | …11001111001101011 |
3 | 1021010111000012200220 |
4 | 30110012321321223 |
5 | 204034344144420 |
6 | 10024010501123 |
7 | 645442215666 |
oct | 142406717153 |
9 | 37114005626 |
10 | 13222256235 |
11 | 56756898a1 |
12 | 26901347a3 |
13 | 132944c376 |
14 | 8d60a26dd |
15 | 525c05840 |
hex | 3141b9e6b |
13222256235 has 8 divisors (see below), whose sum is σ = 21155610000. Its totient is φ = 7051869984.
The previous prime is 13222256213. The next prime is 13222256269. The reversal of 13222256235 is 53265222231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 13222256235 - 26 = 13222256171 is a prime.
It is a super-3 number, since 3×132222562353 (a number of 31 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13222256196 and 13222256205.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 440741860 + ... + 440741889.
It is an arithmetic number, because the mean of its divisors is an integer number (2644451250).
Almost surely, 213222256235 is an apocalyptic number.
13222256235 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13222256235 is a deficient number, since it is larger than the sum of its proper divisors (7933353765).
13222256235 is an equidigital number, since it uses as much as digits as its factorization.
13222256235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 881483757.
The product of its digits is 43200, while the sum is 33.
Adding to 13222256235 its reverse (53265222231), we get a palindrome (66487478466).
The spelling of 13222256235 in words is "thirteen billion, two hundred twenty-two million, two hundred fifty-six thousand, two hundred thirty-five".
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