Base | Representation |
---|---|
bin | 11110000100000101111011… |
… | …101001010111110100100011 |
3 | 122100011100202022021122022220 |
4 | 132010011323221113310203 |
5 | 114312313433004303103 |
6 | 1145114124331402123 |
7 | 36564525226415544 |
oct | 3604057351276443 |
9 | 570140668248286 |
10 | 132222642650403 |
11 | 39148342814628 |
12 | 129b57735b3343 |
13 | 58a170716a2c6 |
14 | 2491877d9a4cb |
15 | 104463376dc53 |
hex | 78417ba57d23 |
132222642650403 has 4 divisors (see below), whose sum is σ = 176296856867208. Its totient is φ = 88148428433600.
The previous prime is 132222642650341. The next prime is 132222642650507. The reversal of 132222642650403 is 304056246222231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132222642650403 - 29 = 132222642649891 is a prime.
It is not an unprimeable number, because it can be changed into a prime (132222642690403) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22037107108398 + ... + 22037107108403.
It is an arithmetic number, because the mean of its divisors is an integer number (44074214216802).
Almost surely, 2132222642650403 is an apocalyptic number.
132222642650403 is a deficient number, since it is larger than the sum of its proper divisors (44074214216805).
132222642650403 is an equidigital number, since it uses as much as digits as its factorization.
132222642650403 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44074214216804.
The product of its (nonzero) digits is 829440, while the sum is 42.
Adding to 132222642650403 its reverse (304056246222231), we get a palindrome (436278888872634).
The spelling of 132222642650403 in words is "one hundred thirty-two trillion, two hundred twenty-two billion, six hundred forty-two million, six hundred fifty thousand, four hundred three".
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