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13222344145 = 53298780167
BaseRepresentation
bin11000101000001110…
…01111010111010001
31021010111011200021211
430110013033113101
5204034410003040
610024012420121
7645443033203
oct142407172721
937114150254
1013222344145
11567573994a
122690177641
13132948039a
148d60c6773
15525c218ea
hex3141cf5d1

13222344145 has 8 divisors (see below), whose sum is σ = 15867491904. Its totient is φ = 10577422704.

The previous prime is 13222344139. The next prime is 13222344173. The reversal of 13222344145 is 54144322231.

13222344145 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 13222344145 - 213 = 13222335953 is a prime.

It is a Duffinian number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 124852 + ... + 205018.

It is an arithmetic number, because the mean of its divisors is an integer number (1983436488).

Almost surely, 213222344145 is an apocalyptic number.

It is an amenable number.

13222344145 is a deficient number, since it is larger than the sum of its proper divisors (2645147759).

13222344145 is an equidigital number, since it uses as much as digits as its factorization.

13222344145 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 113159.

The product of its digits is 23040, while the sum is 31.

Adding to 13222344145 its reverse (54144322231), we get a palindrome (67366666376).

The spelling of 13222344145 in words is "thirteen billion, two hundred twenty-two million, three hundred forty-four thousand, one hundred forty-five".

Divisors: 1 5 32987 80167 164935 400835 2644468829 13222344145