Base | Representation |
---|---|
bin | 11110000100001100111000… |
… | …010101001111011001101001 |
3 | 122100012002000020200120020120 |
4 | 132010030320111033121221 |
5 | 114312424222411443103 |
6 | 1145121400521513453 |
7 | 36565211140344561 |
oct | 3604147025173151 |
9 | 570162006616216 |
10 | 132230103234153 |
11 | 39150521053621 |
12 | 129b70b6042889 |
13 | 58a2325a073c2 |
14 | 2491d84b6bda1 |
15 | 104491d717253 |
hex | 78433854f669 |
132230103234153 has 16 divisors (see below), whose sum is σ = 185586826996800. Its totient is φ = 83513426673600.
The previous prime is 132230103234149. The next prime is 132230103234181. The reversal of 132230103234153 is 351432301032231.
It is not a de Polignac number, because 132230103234153 - 22 = 132230103234149 is a prime.
It is not an unprimeable number, because it can be changed into a prime (132230103234143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10852843 + ... + 19551071.
It is an arithmetic number, because the mean of its divisors is an integer number (11599176687300).
Almost surely, 2132230103234153 is an apocalyptic number.
It is an amenable number.
132230103234153 is a deficient number, since it is larger than the sum of its proper divisors (53356723762647).
132230103234153 is a wasteful number, since it uses less digits than its factorization.
132230103234153 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8964952.
The product of its (nonzero) digits is 38880, while the sum is 33.
Adding to 132230103234153 its reverse (351432301032231), we get a palindrome (483662404266384).
The spelling of 132230103234153 in words is "one hundred thirty-two trillion, two hundred thirty billion, one hundred three million, two hundred thirty-four thousand, one hundred fifty-three".
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