Base | Representation |
---|---|
bin | 11110000100001101001011… |
… | …100101110011011110100011 |
3 | 122100012002211202200012201011 |
4 | 132010031023211303132203 |
5 | 114312430403120441311 |
6 | 1145121452543121351 |
7 | 36565222142623051 |
oct | 3604151345633643 |
9 | 570162752605634 |
10 | 132230426343331 |
11 | 391506774812a8 |
12 | 129b71862a3257 |
13 | 58a2377936874 |
14 | 2491db5a391d1 |
15 | 104493bc8d321 |
hex | 78434b9737a3 |
132230426343331 has 4 divisors (see below), whose sum is σ = 132230683160992. Its totient is φ = 132230169525672.
The previous prime is 132230426343311. The next prime is 132230426343341. The reversal of 132230426343331 is 133343624032231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132230426343331 - 211 = 132230426341283 is a prime.
It is a super-2 number, since 2×1322304263433312 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132230426343311) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 127634955 + ... + 128666788.
It is an arithmetic number, because the mean of its divisors is an integer number (33057670790248).
Almost surely, 2132230426343331 is an apocalyptic number.
132230426343331 is a deficient number, since it is larger than the sum of its proper divisors (256817661).
132230426343331 is an equidigital number, since it uses as much as digits as its factorization.
132230426343331 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 256817660.
The product of its (nonzero) digits is 559872, while the sum is 40.
The spelling of 132230426343331 in words is "one hundred thirty-two trillion, two hundred thirty billion, four hundred twenty-six million, three hundred forty-three thousand, three hundred thirty-one".
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