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132230426343331 = 515917256301743
BaseRepresentation
bin11110000100001101001011…
…100101110011011110100011
3122100012002211202200012201011
4132010031023211303132203
5114312430403120441311
61145121452543121351
736565222142623051
oct3604151345633643
9570162752605634
10132230426343331
11391506774812a8
12129b71862a3257
1358a2377936874
142491db5a391d1
15104493bc8d321
hex78434b9737a3

132230426343331 has 4 divisors (see below), whose sum is σ = 132230683160992. Its totient is φ = 132230169525672.

The previous prime is 132230426343311. The next prime is 132230426343341. The reversal of 132230426343331 is 133343624032231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132230426343331 - 211 = 132230426341283 is a prime.

It is a super-2 number, since 2×1322304263433312 (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132230426343311) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 127634955 + ... + 128666788.

It is an arithmetic number, because the mean of its divisors is an integer number (33057670790248).

Almost surely, 2132230426343331 is an apocalyptic number.

132230426343331 is a deficient number, since it is larger than the sum of its proper divisors (256817661).

132230426343331 is an equidigital number, since it uses as much as digits as its factorization.

132230426343331 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 256817660.

The product of its (nonzero) digits is 559872, while the sum is 40.

The spelling of 132230426343331 in words is "one hundred thirty-two trillion, two hundred thirty billion, four hundred twenty-six million, three hundred forty-three thousand, three hundred thirty-one".

Divisors: 1 515917 256301743 132230426343331