Base | Representation |
---|---|
bin | 10011001111100000011… |
… | …010111010011000010011 |
3 | 11200102010202120120121111 |
4 | 103033200122322120103 |
5 | 133131102422023443 |
6 | 2451244313034151 |
7 | 164351216330554 |
oct | 23174032723023 |
9 | 4612122516544 |
10 | 1322320111123 |
11 | 46a87a259020 |
12 | 1943363b5957 |
13 | 9790436909b |
14 | 48001a5632b |
15 | 245e36d669d |
hex | 133e06ba613 |
1322320111123 has 16 divisors (see below), whose sum is σ = 1445923432800. Its totient is φ = 1199283148800.
The previous prime is 1322320111067. The next prime is 1322320111139. The reversal of 1322320111123 is 3211110232231.
It is not a de Polignac number, because 1322320111123 - 29 = 1322320110611 is a prime.
It is a super-2 number, since 2×13223201111232 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1322320111094 and 1322320111103.
It is not an unprimeable number, because it can be changed into a prime (1322320111163) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 32114353 + ... + 32155501.
It is an arithmetic number, because the mean of its divisors is an integer number (90370214550).
Almost surely, 21322320111123 is an apocalyptic number.
1322320111123 is a deficient number, since it is larger than the sum of its proper divisors (123603321677).
1322320111123 is a wasteful number, since it uses less digits than its factorization.
1322320111123 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 47958.
The product of its (nonzero) digits is 432, while the sum is 22.
Adding to 1322320111123 its reverse (3211110232231), we get a palindrome (4533430343354).
The spelling of 1322320111123 in words is "one trillion, three hundred twenty-two billion, three hundred twenty million, one hundred eleven thousand, one hundred twenty-three".
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