132232712035 has 4 divisors (see below), whose sum is σ = 158679254448. Its totient is φ = 105786169624.

The previous prime is 132232712011. The next prime is 132232712041. The reversal of 132232712035 is 530217232231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 530217232231 = 643 ⋅824599117.

It is a cyclic number.

It is not a de Polignac number, because 132232712035 - 2²¹ = 132230614883 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132232711988 and 132232712006.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13223271199 + ... + 13223271208.

It is an arithmetic number, because the mean of its divisors is an integer number (39669813612).

Almost surely, 2^132232712035 is an apocalyptic number.

132232712035 is a deficient number, since it is larger than the sum of its proper divisors (26446542413).

132232712035 is an equidigital number, since it uses as much as digits as its factorization.

132232712035 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26446542412.

The product of its (nonzero) digits is 15120, while the sum is 31.

Adding to 132232712035 its reverse (530217232231), we get a palindrome (662449944266).

The spelling of 132232712035 in words is "one hundred thirty-two billion, two hundred thirty-two million, seven hundred twelve thousand, thirty-five".