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13223661140651 = 131017204703127
BaseRepresentation
bin1100000001101101111110…
…0111111111101010101011
31201211011120200101200211112
43000123133213333222223
53213124024223000101
644042511023020535
72533243436051633
oct300333747775253
951734520350745
1013223661140651
114239139a79095
121596a0143a74b
1374bca801b520
1433a0587356c3
1517de9eeb46bb
hexc06df9ffaab

13223661140651 has 4 divisors (see below), whose sum is σ = 14240865843792. Its totient is φ = 12206456437512.

The previous prime is 13223661140609. The next prime is 13223661140671. The reversal of 13223661140651 is 15604116632231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13223661140651 - 26 = 13223661140587 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13223661140599 and 13223661140608.

It is not an unprimeable number, because it can be changed into a prime (13223661140671) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 508602351551 + ... + 508602351576.

It is an arithmetic number, because the mean of its divisors is an integer number (3560216460948).

Almost surely, 213223661140651 is an apocalyptic number.

13223661140651 is a deficient number, since it is larger than the sum of its proper divisors (1017204703141).

13223661140651 is a wasteful number, since it uses less digits than its factorization.

13223661140651 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1017204703140.

The product of its (nonzero) digits is 155520, while the sum is 41.

Adding to 13223661140651 its reverse (15604116632231), we get a palindrome (28827777772882).

The spelling of 13223661140651 in words is "thirteen trillion, two hundred twenty-three billion, six hundred sixty-one million, one hundred forty thousand, six hundred fifty-one".

Divisors: 1 13 1017204703127 13223661140651