Base | Representation |
---|---|
bin | 11000101000100011… |
… | …00010011001100011 |
3 | 1021010200020211011222 |
4 | 30110101202121203 |
5 | 204041102343210 |
6 | 10024150325255 |
7 | 645505005203 |
oct | 142421423143 |
9 | 37120224158 |
10 | 13225043555 |
11 | 5677212a69 |
12 | 269105982b |
13 | 1329bb6c79 |
14 | 8d65ca403 |
15 | 5260a6655 |
hex | 314462663 |
13225043555 has 8 divisors (see below), whose sum is σ = 16048368000. Its totient is φ = 10461157696.
The previous prime is 13225043509. The next prime is 13225043569. The reversal of 13225043555 is 55534052231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 13225043555 - 210 = 13225042531 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 14859155 + ... + 14860044.
It is an arithmetic number, because the mean of its divisors is an integer number (2006046000).
Almost surely, 213225043555 is an apocalyptic number.
13225043555 is a deficient number, since it is larger than the sum of its proper divisors (2823324445).
13225043555 is an equidigital number, since it uses as much as digits as its factorization.
13225043555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 29719293.
The product of its (nonzero) digits is 90000, while the sum is 35.
Adding to 13225043555 its reverse (55534052231), we get a palindrome (68759095786).
The spelling of 13225043555 in words is "thirteen billion, two hundred twenty-five million, forty-three thousand, five hundred fifty-five".
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