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13225130033 = 69463190391
BaseRepresentation
bin11000101000100011…
…10111100000110001
31021010200102012210212
430110101313200301
5204041113130113
610024152233505
7645505515263
oct142421674061
937120365725
1013225130033
115677271a35
12269109b895
131329c1743b
148d660db33
155260c20a8
hex314477831

13225130033 has 4 divisors (see below), whose sum is σ = 13225389888. Its totient is φ = 13224870180.

The previous prime is 13225130003. The next prime is 13225130047. The reversal of 13225130033 is 33003152231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13225130033 - 26 = 13225129969 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13225129990 and 13225130008.

It is not an unprimeable number, because it can be changed into a prime (13225130003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25733 + ... + 164658.

It is an arithmetic number, because the mean of its divisors is an integer number (3306347472).

Almost surely, 213225130033 is an apocalyptic number.

It is an amenable number.

13225130033 is a deficient number, since it is larger than the sum of its proper divisors (259855).

13225130033 is an equidigital number, since it uses as much as digits as its factorization.

13225130033 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 259854.

The product of its (nonzero) digits is 1620, while the sum is 23.

Adding to 13225130033 its reverse (33003152231), we get a palindrome (46228282264).

The spelling of 13225130033 in words is "thirteen billion, two hundred twenty-five million, one hundred thirty thousand, thirty-three".

Divisors: 1 69463 190391 13225130033