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13225347851 = 24175471803
BaseRepresentation
bin11000101000100101…
…01100101100001011
31021010200211021121012
430110102230230023
5204041142112401
610024201034135
7645510413312
oct142422545413
937120737535
1013225347851
115677400651
12269118594b
131329c92621
148d6669279
155261168bb
hex3144acb0b

13225347851 has 4 divisors (see below), whose sum is σ = 13230822072. Its totient is φ = 13219873632.

The previous prime is 13225347827. The next prime is 13225347857. The reversal of 13225347851 is 15874352231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15874352231 = 109145636259.

It is a cyclic number.

It is not a de Polignac number, because 13225347851 - 26 = 13225347787 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13225347799 and 13225347808.

It is not an unprimeable number, because it can be changed into a prime (13225347857) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2733485 + ... + 2738318.

It is an arithmetic number, because the mean of its divisors is an integer number (3307705518).

Almost surely, 213225347851 is an apocalyptic number.

13225347851 is a deficient number, since it is larger than the sum of its proper divisors (5474221).

13225347851 is an equidigital number, since it uses as much as digits as its factorization.

13225347851 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5474220.

The product of its digits is 201600, while the sum is 41.

The spelling of 13225347851 in words is "thirteen billion, two hundred twenty-five million, three hundred forty-seven thousand, eight hundred fifty-one".

Divisors: 1 2417 5471803 13225347851