132254000560243 has 4 divisors (see below), whose sum is σ = 140033647652040. Its totient is φ = 124474353468448.

The previous prime is 132254000560211. The next prime is 132254000560273. The reversal of 132254000560243 is 342065000452231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 132254000560243 - 2⁵ = 132254000560211 is a prime.

It is a super-2 number, since 2×132254000560243² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132254000560273) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3889823545873 + ... + 3889823545906.

It is an arithmetic number, because the mean of its divisors is an integer number (35008411913010).

Almost surely, 2^{132254000560243} is an apocalyptic number.

132254000560243 is a deficient number, since it is larger than the sum of its proper divisors (7779647091797).

132254000560243 is an equidigital number, since it uses as much as digits as its factorization.

132254000560243 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7779647091796.

The product of its (nonzero) digits is 172800, while the sum is 37.

The spelling of 132254000560243 in words is "one hundred thirty-two trillion, two hundred fifty-four billion, five hundred sixty thousand, two hundred forty-three".