Base | Representation |
---|---|
bin | 11110000100101010101101… |
… | …010100000000010000010011 |
3 | 122100022010200021212002201212 |
4 | 132010222231110000100103 |
5 | 114313440320414142230 |
6 | 1145144214535450335 |
7 | 36600423615525641 |
oct | 3604525524002023 |
9 | 570263607762655 |
10 | 132262130615315 |
11 | 39163066736078 |
12 | 12a01353b269ab |
13 | 58a535b11280c |
14 | 249374255c191 |
15 | 1045695311895 |
hex | 784aad500413 |
132262130615315 has 4 divisors (see below), whose sum is σ = 158714556738384. Its totient is φ = 105809704492248.
The previous prime is 132262130615309. The next prime is 132262130615339. The reversal of 132262130615315 is 513516031262231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 132262130615315 - 210 = 132262130614291 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13226213061527 + ... + 13226213061536.
It is an arithmetic number, because the mean of its divisors is an integer number (39678639184596).
Almost surely, 2132262130615315 is an apocalyptic number.
132262130615315 is a deficient number, since it is larger than the sum of its proper divisors (26452426123069).
132262130615315 is an equidigital number, since it uses as much as digits as its factorization.
132262130615315 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26452426123068.
The product of its (nonzero) digits is 194400, while the sum is 41.
Adding to 132262130615315 its reverse (513516031262231), we get a palindrome (645778161877546).
The spelling of 132262130615315 in words is "one hundred thirty-two trillion, two hundred sixty-two billion, one hundred thirty million, six hundred fifteen thousand, three hundred fifteen".
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