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13230100113 = 331142259141
BaseRepresentation
bin11000101001001001…
…10100111010010001
31021011000202201110220
430110210310322101
5204043401200423
610024450543253
7645565665306
oct142444647221
937130681426
1013230100113
11567a05703a
122692897b29
13132ac67709
148d71450ad
155267549e3
hex314934e91

13230100113 has 8 divisors (see below), whose sum is σ = 18209170176. Its totient is φ = 8535548400.

The previous prime is 13230100099. The next prime is 13230100133. The reversal of 13230100113 is 31100103231.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13230100113 - 216 = 13230034577 is a prime.

It is a super-2 number, since 2×132301001132 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13230100092 and 13230100101.

It is not an unprimeable number, because it can be changed into a prime (13230100133) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 71129478 + ... + 71129663.

It is an arithmetic number, because the mean of its divisors is an integer number (2276146272).

Almost surely, 213230100113 is an apocalyptic number.

It is an amenable number.

13230100113 is a deficient number, since it is larger than the sum of its proper divisors (4979070063).

13230100113 is a wasteful number, since it uses less digits than its factorization.

13230100113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 142259175.

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 13230100113 its reverse (31100103231), we get a palindrome (44330203344).

The spelling of 13230100113 in words is "thirteen billion, two hundred thirty million, one hundred thousand, one hundred thirteen".

Divisors: 1 3 31 93 142259141 426777423 4410033371 13230100113