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13230102121 = 59224239019
BaseRepresentation
bin11000101001001001…
…10101011001101001
31021011000202211020021
430110210311121221
5204043401231441
610024451000441
7645566004205
oct142444653151
937130684207
1013230102121
11567a0585a5
122692899121
13132ac685c2
148d7145b05
155267553d1
hex314935669

13230102121 has 4 divisors (see below), whose sum is σ = 13454341200. Its totient is φ = 13005863044.

The previous prime is 13230102103. The next prime is 13230102133. The reversal of 13230102121 is 12120103231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 13230102121 - 27 = 13230101993 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13230102095 and 13230102104.

It is not an unprimeable number, because it can be changed into a prime (13230102101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 112119451 + ... + 112119568.

It is an arithmetic number, because the mean of its divisors is an integer number (3363585300).

Almost surely, 213230102121 is an apocalyptic number.

It is an amenable number.

13230102121 is a deficient number, since it is larger than the sum of its proper divisors (224239079).

13230102121 is an equidigital number, since it uses as much as digits as its factorization.

13230102121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 224239078.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13230102121 its reverse (12120103231), we get a palindrome (25350205352).

The spelling of 13230102121 in words is "thirteen billion, two hundred thirty million, one hundred two thousand, one hundred twenty-one".

Divisors: 1 59 224239019 13230102121