132301115 has 4 divisors (see below), whose sum is σ = 158761344. Its totient is φ = 105840888.

The previous prime is 132301109. The next prime is 132301151. The reversal of 132301115 is 511103231.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 511103231 = 31 ⋅16487201.

It is a cyclic number.

It is not a de Polignac number, because 132301115 - 2⁶ = 132301051 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 132301093 and 132301102.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13230107 + ... + 13230116.

It is an arithmetic number, because the mean of its divisors is an integer number (39690336).

Almost surely, 2^132301115 is an apocalyptic number.

132301115 is a deficient number, since it is larger than the sum of its proper divisors (26460229).

132301115 is an equidigital number, since it uses as much as digits as its factorization.

132301115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26460228.

The product of its (nonzero) digits is 90, while the sum is 17.

The square root of 132301115 is about 11502.2221766057. Note that the first 3 decimals coincide. The cubic root of 132301115 is about 509.5512071324.

Adding to 132301115 its reverse (511103231), we get a palindrome (643404346).

The spelling of 132301115 in words is "one hundred thirty-two million, three hundred one thousand, one hundred fifteen".