Base | Representation |
---|---|
bin | 1100000010000110011111… |
… | …0001010100011001010011 |
3 | 1201211210120012011021000122 |
4 | 3000201213301110121103 |
5 | 3213231013001103043 |
6 | 44045515524140455 |
7 | 2533565454434006 |
oct | 300414761243123 |
9 | 51753505137018 |
10 | 13230240253523 |
11 | 4240a05790a57 |
12 | 159813883772b |
13 | 74c7b607ba17 |
14 | 33a4c041153d |
15 | 17e237891368 |
hex | c0867c54653 |
13230240253523 has 4 divisors (see below), whose sum is σ = 13280545349808. Its totient is φ = 13179935157240.
The previous prime is 13230240253501. The next prime is 13230240253537. The reversal of 13230240253523 is 32535204203231.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13230240253523 - 216 = 13230240187987 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13230240253823) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25152547748 + ... + 25152548273.
It is an arithmetic number, because the mean of its divisors is an integer number (3320136337452).
Almost surely, 213230240253523 is an apocalyptic number.
13230240253523 is a deficient number, since it is larger than the sum of its proper divisors (50305096285).
13230240253523 is an equidigital number, since it uses as much as digits as its factorization.
13230240253523 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50305096284.
The product of its (nonzero) digits is 129600, while the sum is 35.
Adding to 13230240253523 its reverse (32535204203231), we get a palindrome (45765444456754).
The spelling of 13230240253523 in words is "thirteen trillion, two hundred thirty billion, two hundred forty million, two hundred fifty-three thousand, five hundred twenty-three".
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