Base | Representation |
---|---|
bin | 11110000101010010000110… |
… | …100100111010111000110001 |
3 | 122100110011212020101101020220 |
4 | 132011102012210322320301 |
5 | 114320133433141130223 |
6 | 1145215452151123253 |
7 | 36603452060051226 |
oct | 3605220644727061 |
9 | 570404766341226 |
10 | 132304430411313 |
11 | 39179aa2885966 |
12 | 12a0959a073529 |
13 | 58a933c7983c4 |
14 | 24957d634394d |
15 | 104681db796e3 |
hex | 78548693ae31 |
132304430411313 has 8 divisors (see below), whose sum is σ = 176408561917728. Its totient is φ = 88201626256224.
The previous prime is 132304430411273. The next prime is 132304430411327. The reversal of 132304430411313 is 313114034403231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 132304430411313 - 224 = 132304413634097 is a prime.
It is not an unprimeable number, because it can be changed into a prime (132304430411383) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 331605231 + ... + 332003972.
It is an arithmetic number, because the mean of its divisors is an integer number (22051070239716).
Almost surely, 2132304430411313 is an apocalyptic number.
It is an amenable number.
132304430411313 is a deficient number, since it is larger than the sum of its proper divisors (44104131506415).
132304430411313 is an equidigital number, since it uses as much as digits as its factorization.
132304430411313 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 663675663.
The product of its (nonzero) digits is 31104, while the sum is 33.
Adding to 132304430411313 its reverse (313114034403231), we get a palindrome (445418464814544).
The spelling of 132304430411313 in words is "one hundred thirty-two trillion, three hundred four billion, four hundred thirty million, four hundred eleven thousand, three hundred thirteen".
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