Base | Representation |
---|---|
bin | 11000101001001101… |
… | …01100111100010011 |
3 | 1021011001200200220011 |
4 | 30110212230330103 |
5 | 204044012414023 |
6 | 10024505255351 |
7 | 645603113554 |
oct | 142446547423 |
9 | 37131620804 |
10 | 13230591763 |
11 | 567a362464 |
12 | 2692a94557 |
13 | 132b0aa42c |
14 | 8d723232b |
15 | 52680050d |
hex | 3149acf13 |
13230591763 has 4 divisors (see below), whose sum is σ = 13318211728. Its totient is φ = 13142971800.
The previous prime is 13230591743. The next prime is 13230591797. The reversal of 13230591763 is 36719503231.
13230591763 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13230591763 - 233 = 4640657171 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13230591733) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 43809756 + ... + 43810057.
It is an arithmetic number, because the mean of its divisors is an integer number (3329552932).
Almost surely, 213230591763 is an apocalyptic number.
13230591763 is a deficient number, since it is larger than the sum of its proper divisors (87619965).
13230591763 is an equidigital number, since it uses as much as digits as its factorization.
13230591763 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 87619964.
The product of its (nonzero) digits is 102060, while the sum is 40.
The spelling of 13230591763 in words is "thirteen billion, two hundred thirty million, five hundred ninety-one thousand, seven hundred sixty-three".
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