1323101102131 has 4 divisors (see below), whose sum is σ = 1345526544600. Its totient is φ = 1300675659664.

The previous prime is 1323101102123. The next prime is 1323101102179. The reversal of 1323101102131 is 1312011013231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1323101102131 - 2³ = 1323101102123 is a prime.

It is a super-2 number, since 2×1323101102131² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1323101102099 and 1323101102108.

It is not an unprimeable number, because it can be changed into a prime (1323101102111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11212721146 + ... + 11212721263.

It is an arithmetic number, because the mean of its divisors is an integer number (336381636150).

Almost surely, 2^{1323101102131} is an apocalyptic number.

1323101102131 is a deficient number, since it is larger than the sum of its proper divisors (22425442469).

1323101102131 is an equidigital number, since it uses as much as digits as its factorization.

1323101102131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22425442468.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 1323101102131 its reverse (1312011013231), we get a palindrome (2635112115362).

The spelling of 1323101102131 in words is "one trillion, three hundred twenty-three billion, one hundred one million, one hundred two thousand, one hundred thirty-one".