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132312231113 = 251527140363
BaseRepresentation
bin111101100111001101…
…1000110110011001001
3110122112001210202102012
41323032123012303021
54131433412343423
6140441114145305
712362551256636
oct1731633066311
9418461722365
10132312231113
1151127894637
1221787122235
13c627c3cc1a
1465925dd18d
153695d4e078
hex1ece6c6cc9

132312231113 has 4 divisors (see below), whose sum is σ = 132839371728. Its totient is φ = 131785090500.

The previous prime is 132312231101. The next prime is 132312231131. The reversal of 132312231113 is 311132213231.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 132312231113 - 212 = 132312227017 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (132312231013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 263569931 + ... + 263570432.

It is an arithmetic number, because the mean of its divisors is an integer number (33209842932).

Almost surely, 2132312231113 is an apocalyptic number.

It is an amenable number.

132312231113 is a deficient number, since it is larger than the sum of its proper divisors (527140615).

132312231113 is an equidigital number, since it uses as much as digits as its factorization.

132312231113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 527140614.

The product of its digits is 648, while the sum is 23.

Adding to 132312231113 its reverse (311132213231), we get a palindrome (443444444344).

The spelling of 132312231113 in words is "one hundred thirty-two billion, three hundred twelve million, two hundred thirty-one thousand, one hundred thirteen".

Divisors: 1 251 527140363 132312231113