Base | Representation |
---|---|
bin | 11110000101011100001010… |
… | …010110010001110101010011 |
3 | 122100111012201221210020002211 |
4 | 132011130022112101311103 |
5 | 114320323043130201433 |
6 | 1145224440015252551 |
7 | 36604313526306232 |
oct | 3605341226216523 |
9 | 570435657706084 |
10 | 132315231100243 |
11 | 39183635561364 |
12 | 12a0b6b321a157 |
13 | 58aa37131a1b9 |
14 | 249613c970b19 |
15 | 1046c51e988cd |
hex | 78570a591d53 |
132315231100243 has 4 divisors (see below), whose sum is σ = 132315571433080. Its totient is φ = 132314890767408.
The previous prime is 132315231100237. The next prime is 132315231100249. The reversal of 132315231100243 is 342001132513231.
It is a semiprime because it is the product of two primes.
It is an interprime number because it is at equal distance from previous prime (132315231100237) and next prime (132315231100249).
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-132315231100243 is a prime.
It is a super-2 number, since 2×1323152311002432 (a number of 29 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132315231100249) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 169582578 + ... + 170361031.
It is an arithmetic number, because the mean of its divisors is an integer number (33078892858270).
Almost surely, 2132315231100243 is an apocalyptic number.
132315231100243 is a deficient number, since it is larger than the sum of its proper divisors (340332837).
132315231100243 is an equidigital number, since it uses as much as digits as its factorization.
132315231100243 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 340332836.
The product of its (nonzero) digits is 12960, while the sum is 31.
Adding to 132315231100243 its reverse (342001132513231), we get a palindrome (474316363613474).
The spelling of 132315231100243 in words is "one hundred thirty-two trillion, three hundred fifteen billion, two hundred thirty-one million, one hundred thousand, two hundred forty-three".
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