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13232140403 = 74111785473
BaseRepresentation
bin11000101001011001…
…00111000001110011
31021011011121101020012
430110230213001303
5204044411443103
610025002405135
7645622223546
oct142454470163
937134541205
1013232140403
11568021aa29
1226935007ab
13132b5002a1
148d751685d
15526a092d8
hex314b27073

13232140403 has 4 divisors (see below), whose sum is σ = 13233933288. Its totient is φ = 13230347520.

The previous prime is 13232140367. The next prime is 13232140421. The reversal of 13232140403 is 30404123231.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13232140403 - 28 = 13232140147 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13232140433) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 885326 + ... + 900147.

It is an arithmetic number, because the mean of its divisors is an integer number (3308483322).

Almost surely, 213232140403 is an apocalyptic number.

13232140403 is a deficient number, since it is larger than the sum of its proper divisors (1792885).

13232140403 is an equidigital number, since it uses as much as digits as its factorization.

13232140403 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1792884.

The product of its (nonzero) digits is 1728, while the sum is 23.

Adding to 13232140403 its reverse (30404123231), we get a palindrome (43636263634).

The spelling of 13232140403 in words is "thirteen billion, two hundred thirty-two million, one hundred forty thousand, four hundred three".

Divisors: 1 7411 1785473 13232140403