13232251041241 has 4 divisors (see below), whose sum is σ = 13254268098484. Its totient is φ = 13210233984000.

The previous prime is 13232251041239. The next prime is 13232251041257. The reversal of 13232251041241 is 14214015223231.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10940191299216 + 2292059742025 = 3307596^2 + 1513955^2 .

It is a cyclic number.

It is not a de Polignac number, because 13232251041241 - 2¹ = 13232251041239 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13232251041221) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 11008527720 + ... + 11008528921.

It is an arithmetic number, because the mean of its divisors is an integer number (3313567024621).

Almost surely, 2^{13232251041241} is an apocalyptic number.

It is an amenable number.

13232251041241 is a deficient number, since it is larger than the sum of its proper divisors (22017057243).

13232251041241 is an equidigital number, since it uses as much as digits as its factorization.

13232251041241 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 22017057242.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 13232251041241 its reverse (14214015223231), we get a palindrome (27446266264472).

The spelling of 13232251041241 in words is "thirteen trillion, two hundred thirty-two billion, two hundred fifty-one million, forty-one thousand, two hundred forty-one".