Base | Representation |
---|---|
bin | 11110000101101101101001… |
… | …111011010110101111000001 |
3 | 122100120000020000010000222021 |
4 | 132011231221323112233001 |
5 | 114321130030204234403 |
6 | 1145241223525241441 |
7 | 36605550146626525 |
oct | 3605555173265701 |
9 | 570500200100867 |
10 | 132334014524353 |
11 | 391905a4292964 |
12 | 12a13275863281 |
13 | 58ac075948935 |
14 | 249700144dd85 |
15 | 10474a10028bd |
hex | 785b69ed6bc1 |
132334014524353 has 8 divisors (see below), whose sum is σ = 133042435854336. Its totient is φ = 131625755414400.
The previous prime is 132334014524347. The next prime is 132334014524443. The reversal of 132334014524353 is 353425410433231.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 132334014524353 - 225 = 132333980969921 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (132334014524323) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 38918928 + ... + 42182353.
It is an arithmetic number, because the mean of its divisors is an integer number (16630304481792).
Almost surely, 2132334014524353 is an apocalyptic number.
It is an amenable number.
132334014524353 is a deficient number, since it is larger than the sum of its proper divisors (708421329983).
132334014524353 is an equidigital number, since it uses as much as digits as its factorization.
132334014524353 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 81110015.
The product of its (nonzero) digits is 1555200, while the sum is 43.
Adding to 132334014524353 its reverse (353425410433231), we get a palindrome (485759424957584).
The spelling of 132334014524353 in words is "one hundred thirty-two trillion, three hundred thirty-four billion, fourteen million, five hundred twenty-four thousand, three hundred fifty-three".
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